How do you simplify $x^{- 2} \cdot {(x y^{2})}^{4}$ $x^ { - 2} \cdot ( x y ^ { 2} ) ^ { 4}$ ?

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How do you simplify $x^{- 2} \cdot {(x y^{2})}^{4}$ $x^ { - 2} \cdot ( x y ^ { 2} ) ^ { 4}$ ?

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Answer 1 · 2018-03-31T05:35:16

$x^{2} \cdot y^{8}$ $x^2*y^8$

Explanation:

bcoz, $x^{- 2} \cdot {(x y^{2})}^{4}$ $x^-2*(xy^2)^4$ can be written as,
$\frac{1}{x^{2}} \cdot x^{4} y^{8}$ $1/x^2*x^4y^8$
i.e. $x^{2} \cdot y^{8}$ $x^2*y^8$

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How do you simplify $x^{- 2} \cdot {(x y^{2})}^{4}$ $x^ { - 2} \cdot ( x y ^ { 2} ) ^ { 4}$ ?

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How do you simplify $x^{- 2} \cdot {(x y^{2})}^{4}$ $x^ { - 2} \cdot ( x y ^ { 2} ) ^ { 4}$ ?