How do you simplify $\frac{1}{3} n (9 n - 15)$ $\frac{1}{3} n( 9n - 15)$ ?

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Answer 1 · 2018-03-31T09:14:48

$n (3 n - 5)$ $n(3n-5)$

= $\frac{9 n^{2}}{3} - \frac{15 n}{3}$ $(9n^2)/3-(15n)/3$

= $3 n^{2} - 5 n$ $3n^2-5n$

= $n (3 n - 5)$ $n(3n-5)$

Hope this helps!

How do you simplify 13n(9n−15)\frac{1}{3} n( 9n - 15)?