How do you multiply $(2 x + 3) (2 x - 3)$ $(2x + 3)(2x - 3)$ ?

Question

2880 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-31T11:21:05

$4 x^{2} - 9$ $4x^2-9$

Use $a^{2} - b^{2} = (a + b) (a - b)$ $a^2 - b^2 =(a+b)(a-b)$

== $4 x^{2} - 6 x + 6 x - 9$ $4x^2-6x+6x-9$

= $4 x^{2} - 9$ $4x^2-9$

Hope this helps!

How do you multiply (2x + 3)(2x - 3)(2x+3)(2x−3)(2x + 3)(2x - 3)?