How do you solve $3 (2 x - 10) - \frac{1}{3} (6 x + 9) = - 1$ $3( 2x - 10) - \frac { 1} { 3} ( 6x + 9) = - 1$ ?

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Answer 1 · 2018-03-31T13:14:43

$x = 8$ $x=8$

$3 (2 x - 10) - \frac{1}{3} (6 x + 9) = - 1$ $3(2x-10)-1/3(6x+9)=-1$

$3 \times 2 x - 3 \times 10 - \frac{1}{3} \times 6 x - \frac{1}{3} \times 9 = - 1$ $3xx2x-3xx10-1/3xx6x-1/3xx9=-1$

$6 x - 30 - 2 x - 3 = - 1$ $6x-30-2x-3=-1$

$(6 x - 2 x) = 30 + 3 - 1$ $(6x-2x)=30+3-1$

$4 x = 32$ $4x=32$

$\frac{4 x}{4} = \frac{32}{4}$ $(4x)/4=32/4$

$x = 8$ $x=8$

How do you solve 3(2x−10)−13(6x+9)=−13( 2x - 10) - \frac { 1} { 3} ( 6x + 9) = - 1?