How do you solve #12x + 3 = 6x + 3#?

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Answer 1 · 2018-03-31T13:38:07

#x=0#

Push all the variables to one side and constants to the other.

We get #12x-6x=3-3#

#6x=0#

So, #x=0#

Answer 2 · 2018-03-31T13:45:09

#color(magenta)(x=0#

#12x+3=6x+3#

#12x-6x=3-3#

#6x=0#

#x=0/6#

#color(magenta)(x=0#

As a check:

#12x+3=6x+3#

#12(0)+3=6(0)+3#

#0+3=0+3#

#color(red)(3=3#

Hence it is proved that #x=0#

~Hope this helps! :)