How do you solve $4 (6 + x) + 2 x = 33$ $4( 6+ x ) + 2x = 33$ ?

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Answer 1 · 2018-03-31T17:57:39

$x = \frac{3}{2} = 1.5$ $x= 3/2=1.5$

$4 (6 + x) + 2 x = 33$ $4( 6+ x ) + 2x = 33$

$\Rightarrow 24 + 4 x + 2 x = 33$ $=> 24 + 4x + 2x = 33$ ------ using distributive property.

$\Rightarrow 24 + 6 x = 33$ $=> 24 + 6x = 33$

$\Rightarrow 6 x = 33 - 24$ $=> 6x = 33-24$ --------- transposition.

$\Rightarrow 6 x = 9$ $=> 6x = 9$

$\Rightarrow x = \frac{9}{6} = \frac{3}{2} = 1.5$ $=> x = 9/6 = 3/2 = 1.5$

$\Rightarrow x = 1.5$ $=> x= 1.5$

Answer 2 · 2018-03-31T18:04:17

$x = 1 \frac{1}{2}$ $x = 1 1/2$

Expand the bracket

$\Rightarrow$ $=>$ $24 + 4 x + 2 x = 33$ $24 + 4x + 2x = 33$

$\Rightarrow$ $=>$ $24 + 6 x = 33$ $24 + 6x = 33$

$\Rightarrow$ $=>$ $6 x = 9$ $6x = 9$

$\Rightarrow$ $=>$ $x = \frac{9}{6}$ $x =9/6$

$\Rightarrow$ $=>$ $x = \frac{3}{2}$ $x = 3/2$

How do you solve 4( 6+ x ) + 2x = 334(6+x)+2x=334( 6+ x ) + 2x = 33?