A ball is thrown upward from the ground with an initial speed of 25 m/s; at the same instant, another ball is dropped from a building 15 m high. After how long will the balls be the same height?
1 Answer
Mar 31, 2018
the time taken for the two balls to meet =
Explanation:
suppose the height is h and after a time t sec the balls meet.
the lower ball will travel a distance say h1 in time t secs
in the same time interval the upper ball will travel
15-h1 distance ,so
15 - h1 =
but you know h1 so substitute it
so finally you get 15 = 25. t
so time taken =
it is as if no g was working.