Mechanics question help on forces?
A miners' cage of mass 420kg contains 3 miners of total mass 280kg. The cage is lowered from rest by a cable. For the first 10 seconds the cage accelerates uniformly and descends a distance of 75 m. The force in the cable during the first 10 seconds is
_N
A miners' cage of mass 420kg contains 3 miners of total mass 280kg. The cage is lowered from rest by a cable. For the first 10 seconds the cage accelerates uniformly and descends a distance of 75 m. The force in the cable during the first 10 seconds is
_N
1 Answer
The force on the cable =
Explanation:
the cage has travelled from rest ,initial velocity say u =0
it has travelled 75m in 10 sec.
so
calculate
now the cage is moving down with an acceleration
if the cable is having tension T then
Mass of cage with miners
force on cable = (M+m) .( g-a) = 700 kg .(10 -1.5)