What is the equation of the tangent line of $f(x)=cos^3x^2$ at $x=0$ ?

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Answer 1 · 2018-04-02T16:59:37

Hence equation of tangent is y=1

Let
$y=cos^3x^2$

Slope of the tangent is

$dy/dx=3cos^2x^2(-sinx^2)(2x)$

$m=-6xcos^2x^2sinx^2$

at x=0

$m=-6xx0xxcos^2 0^2sin0^2$

$m=0$

point of tangency is

$y=cos^3x^2=cos^3 0^2=cos^3 0=(cos0)^2=1^2=1$

Hence equation of tangent is y=1

What is the equation of the tangent line of f(x)=cos^3x^2 f(x)=cos^3x^2 at x=0x=0?