Question

How do you write an equation in slope intercept form given m=1/3, and contains (-3,-15)?

Answer 1

-14 .Check below

Explanation:

Use the equation
`y-y_1 =m(x-x_1)`

Where,

`y_1 = -15`
`x_1 = -3`
`m =1/3`

Next the equation is :
`y+15=1/3(x+3)`
`3y+45=x+3`
Thus,
`y=(x-42)/3`
or u can write
`y=1/3 x - 14`

Now u can use the equation of straight line which is
`Y=mX+c`

compare the above equation with your result and the y-intercept is -14

Answer 2

`y =1/3x -14`

Explanation:

`m` is the slope/gradient of the line

`y =mx + c` is the general equation of the straight line

So we know `y =1/3x +c` and to find the value of `c` we substitute the numbers in the coordinate that the line passes through

`y =1/3x + c` (-3,-15)

`-15 =1/3` `xx` `-3 + c`

`-15 =-1 +c`

`c = -14`

So the equation is `y =1/3x -14`