How do you solve the equation: $(x - 9)^2 = 1$ ?

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Answer 1 · 2018-04-03T12:11:12

$x=10$

= $(x-9)^2=1$

Taking square root on both sides

= $x-9=1$

= $x=10$

Hope it helps!

Answer 2 · 2018-04-03T12:11:38

$x=8,10$

Given: $(x-9)^2=1$

Square root both sides.

$x-9=sqrt(1)$

$x-9=+-1$

We got:

$x_1-9=1,x_2-9=-1$

$:.x_1=1+9,x_2=-1+9$

$x_1=10,x_2=8$

$:.x\in{8,10}$

How do you solve the equation: (x - 9)^2 = 1(x - 9)^2 = 1?