How do you simplify $[\frac{2}{9} \cdot \frac{3}{10} - (- \frac{2}{9} \div \frac{1}{3})] - \frac{2}{5}$ $[\frac { 2} { 9} \cdot \frac { 3} { 10} - ( - \frac { 2} { 9} \div \frac { 1} { 3} ) ] - \frac { 2} { 5}$ ?

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Answer 1 · 2018-04-03T14:11:08

$\frac{1}{3}$ $1/3$

$[\frac{2}{9} \cdot \frac{3}{10} - (- \frac{2}{9} \div \frac{1}{3})] - \frac{2}{5}$ $[2/9*3/10-(-2/9-:1/3)]-2/5$

= $[\frac{6}{90} - (- \frac{2}{9} \cdot \frac{3}{1})] - \frac{2}{5}$ $[6/90-(-2/9*3/1)]-2/5$

= $[\frac{6}{90} + (\frac{2}{9} \cdot \frac{3}{1})] - \frac{2}{5}$ $[6/90+(2/9*3/1)]-2/5$

= $[\frac{6}{90} + \frac{6}{9}] - \frac{2}{5}$ $[6/90+6/9]-2/5$

= $[\frac{6}{90} + \frac{60}{90}] - \frac{2}{5}$ $[6/90+60/90]-2/5$

= $[\frac{66}{90}] - \frac{2}{5}$ $[66/90]-2/5$

= $\frac{66}{90} - \frac{36}{90}$ $66/90-36/90$

= $\frac{30}{90}$ $30/90$

= $\frac{1}{3}$ $1/3$

How do you simplify [29⋅310−(−29÷13)]−25[\frac { 2} { 9} \cdot \frac { 3} { 10} - ( - \frac { 2} { 9} \div \frac { 1} { 3} ) ] - \frac { 2} { 5}?