How do you solve x^2 + 8x - 41 = -8 by completing the square?

1 Answer
elsie ☆
Apr 4, 2018

x^2+8x-41=-8

x^2+8x-41+8=0

x^2+8x-33=0

(x^2+8x+16-16)-33=0 larr you get 16 by dividing 8 by 2 and color(white)"XXXXXXXXXXXXXXXXXX"squaring the value (8-:2= 4), 4^2 = 16

(x+4)^2-49=0

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