What are the solution in the interval [0, 2pie]? sec^2x-tan^2x=0
1 Answer
Apr 4, 2018
See explanation
Explanation:
We want to solve the equation
#sec^2(x)-tan^2(x)=0#
To get a better idea, write this in terms of sine and cosine
#1/cos^2(x)-sin^2(x)/cos^2(x)=0#
To simplify multiply both sides by
#1-sin^2(x)=0#
Thus
#sin^2(x)=1#
#=>sin(x)=+-sqrt(1)#
#=>sin(x)=+-1#
Now i will leave it for you to find the solutions