If 6 is a root of the equation $x^{2} - 8 x + k = 0$ $x^2 - 8x + k= 0$ , what is the value of k?

Question

6688 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-04T15:34:43

k=12
Substitute x=6 in the equation and solve.

Since 6 is a root of the equation, it should satisfy the given equation.

${(6)}^{2} - 8 (6) + k = 0$ $(6)^2-8(6)+k=0$
$36 - 48 + k = 0$ $36-48+k=0$
$- 12 + k = 0$ $-12+k=0$
$k = 12$ $k=12$

If 6 is a root of the equation x2−8x+k=0x^2 - 8x + k= 0, what is the value of k?