What is the #sqrt 657# in simplest radical form? Algebra Radicals and Geometry Connections Simplification of Radical Expressions 1 Answer jk.13 Apr 4, 2018 #sqrt657=3sqrt73# Explanation: #sqrt657=sqrt(9*73)# #sqrt657=3sqrt73# Answer link Related questions How do you simplify radical expressions? How do you simplify radical expressions with fractions? How do you simplify radical expressions with variables? What are radical expressions? How do you simplify #root{3}{-125}#? How do you write # ""^4sqrt(zw)# as a rational exponent? How do you simplify # ""^5sqrt(96)# How do you write # ""^9sqrt(y^3)# as a rational exponent? How do you simplify #sqrt(75a^12b^3c^5)#? How do you simplify #sqrt(50)-sqrt(2)#? See all questions in Simplification of Radical Expressions Impact of this question 5414 views around the world You can reuse this answer Creative Commons License