What is the complete factorization of this? 108−3x ^2

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Answer 1 · 2018-04-05T00:06:56

The fully factored polynomial is #-3(x-6)(x+6)#.

First, factor out #3#:

#color(white)=108-3x^2#

#=color(blue)3(36-x^2)#

Now, use the difference of squares factoring:

#=color(blue)3(6^2-x^2)#

#=color(blue)3(6-x)(6+x)#

If you would like to rearrange the terms so that #x# is in the front:

#=color(blue)3(-x+6)(6+x)#

#=color(blue)3(-x+6)(x+6)#

#=color(blue)3(-(x-6))(x+6)#

#=color(blue)(-3)(x-6)(x+6)#

That's fully factored. Hope this helped!