How do you graph #x-y=6#?

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Answer 1 · 2018-04-05T00:52:58

graph{y=-6+x [-2.75, 17.25, -4.68, 5.32]}

For this, you first solve the equation by starting with moving the x in the equation to the other side

#x-y=6# ----> #-y=6-x#

Then divide the whole equation by negative on to get y by itself

#(-y=6-x)/-1# ----> #y=-6+x#

Now that it is in slope-intercept form pick a number for x and plug it into the equation.

#y=-6+1# ----> #y=-5#

This means that when x is 1 the y value is -5. You can keep doing this to graph the equation