Question

What is the vertex of # y= x^2 - 8?

Answer 1

`V(0,-8)`

Explanation:

As you know from linear graphs the constant at the end (in this case -8) controls the y-intercept. By default on `y=x^2` The vertex is `(0,0)` so by moving the vertex down 8 units the new vertex coordinates are `(0,-8)`.