How do you find the slope and intercept of $18 x + 4 y = 112$ $18x + 4y = 112$ ?

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How do you find the slope and intercept of $18 x + 4 y = 112$ $18x + 4y = 112$ ?

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Answer 1 · 2018-04-05T17:49:03

slope (m)= $- \frac{9}{2}$ $-9/2$
intercept on x-axis= $\frac{56}{9}$ $56/9$
intercept on y-axis= $28$ $28$

Explanation:

$18 x + 4 y = 112$ $18x+4y=112$
$\frac{18 x}{112} + \frac{4 y}{112} = 1$ $(18x)/112+(4y)/112=1$
$\frac{\frac{x}{1}}{\frac{56}{9}} + \frac{y}{28} = 1$ $(x/1)/(56/9)+y/28=1$
intercept on x-axis= $\frac{56}{9}$ $56/9$
intercept on y-axis= $28$ $28$
now, $4 y = - 18 x + 112$ $4y=-18x+112$
$y = - \frac{9}{2} x + 28$ $y=-9/2x+28$
so, slope (m)= $- \frac{9}{2}$ $-9/2$

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How do you find the slope and intercept of $18 x + 4 y = 112$ $18x + 4y = 112$ ?

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Science

Math

Humanities

... and beyond

How do you find the slope and intercept of 18x+4y=11218x + 4y = 112?

1 Answer

Explanation:

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Impact of this question

How do you find the slope and intercept of $18 x + 4 y = 112$ $18x + 4y = 112$ ?