Which is the equation of a circle with center (-5, 2) and radius sqrt 7}?

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Which is the equation of a circle with center (-5, 2) and radius sqrt 7}?

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Answer 1 · 2018-04-05T18:24:09

Circle equation: ${(x - x_{c})}_{c}^{2} + {(y - y_{c})}_{c}^{2} = r^{2}$ $(x-x_c)^2+(y-y_c)^2=r^2$
where $(x_{c}, y_{c})$ $(x_c,y_c)$ is the center and $r$ $r$ is the radius

Explanation:

In your case:
The center is $(- 5, 2)$ $(-5,2)$ and the radius is $r = \sqrt{7}$ $r=sqrt(7)$ $\Rightarrow$ $=>$
${(x - (- 5))}^{2} + {(y - 2)}^{2} = {(\sqrt{7})}^{2}$ $(x-(-5))^2+(y-2)^2=(sqrt(7))^2$
${(x + 5)}^{2} + {(y - 2)}^{2} = 7$ $(x+5)^2+(y-2)^2=7$

The circle equation can be written in many forms, some examples are here.

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Which is the equation of a circle with center (-5, 2) and radius sqrt 7}?

1 Answer

Explanation:

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