Question

How do you simplify `sqrt(-32)`?

Answer 1

`4isqrt2`

Explanation:

`i=sqrt{-1}`

So

`sqrt{-32}=isqrt{32}`

`32 = 2 ^5`

`sqrt{32} = 2 ^2.5= 2^2 times 2^ 0.5 = 4sqrt2`

`sqrt{-32}=4isqrt2`