How do you differentiate 3(x^2-2)^4? Calculus Basic Differentiation Rules Chain Rule 1 Answer Ahmed A. Apr 6, 2018 (dz)/(dx)=24x(x^2-2)^3 Explanation: u=x^2-2 z=3(u)^4 u=x^2-2 (du)/dx=2x Z=3(u)^4 (dz)/(du)=12u^3 we need (dz)/(dx) (du)/dxxx(dz)/(du) (dz)/(dx)=24x(x^2-2)^3 Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1882 views around the world You can reuse this answer Creative Commons License