How do you differentiate #3(x^2-2)^4#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Ahmed A. Apr 6, 2018 #(dz)/(dx)=24x(x^2-2)^3# Explanation: #u=x^2-2# #z=3(u)^4# #u=x^2-2# #(du)/dx=2x# #Z=3(u)^4# #(dz)/(du)=12u^3# we need #(dz)/(dx)# #(du)/dxxx(dz)/(du)# #(dz)/(dx)=24x(x^2-2)^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1664 views around the world You can reuse this answer Creative Commons License