How do you solve $6 (10 - x) = 90$ $6( 10- x ) = 90$ ?

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Answer 1 · 2018-04-06T09:01:03

$x = - 5$ $x=-5$

= $6 (10 - x) + 90$ $6(10-x)+90$

= $60 - 6 x = 90$ $60-6x=90$

= $- 6 x = 90 - 60$ $-6x=90-60$

= $- 6 x = 30$ $-6x=30$

= $x = - 5$ $x=-5$

Check

$6 (10 - (- 5))$ $6(10-(-5))$

$6 \cdot 15$ $6*15$

$90$ $90$

Hope it helps!

How do you solve 6( 10- x ) = 906(10−x)=906( 10- x ) = 90?