Question

Calculate the mass of CO needed to react completely with 50.Og of Fe2 03?

Answer 1

`approx 26.31` grams

Explanation:

We must first create a balanced equation. Carbon monoxide is commonly used in industry to liberate iron from its oxides (which are often found in rock). This produced Carbon dioxide and solid iron.

`Fe_2O_3(s)+3CO(g) ->2Fe(s) +3CO_2(g)`

As `CO` is used to liberate iron from Iron (III) Oxide.

Now we must find how many moles 50.0 g of Iron (III) oxide corresponds to:

`M`(iron (III) oxide)=`159.69 gmol^-1`
`m=50.0`
`n`=?

Using the equation:

`n=(m)/(M)`

`n=(50.0)/(159.69)`

`n approx 0.3131`

Now from the molar ratios we can see that we require 3 moles of `CO` for every 1 mole of Iron (III) oxide.

`n(CO)=3 times 0.3131=0.9393`

Then using the same equation we can find the mass of `CO` required:

`n=(m)/(M)`
`M(CO)=28.01 gmol^-1`

`0.9393=(m)/(28.01)`

`m approx 26.31 g` of `CO` is needed.