How do you use the chain rule to differentiate #y=2(x^3-x)^-2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Timber Lin Apr 6, 2018 #-4(x^3-x)^(-3)*(3x^2-1)# Explanation: #(dy)/dx=d/dx(2(x^3-x)^(-2))# #(dy)/dx=-4(x^3-x)^(-3)*d/dx(x^3-x)# (chain rule) #(dy)/dx=-4(x^3-x)^(-3)*(3x^2-1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1191 views around the world You can reuse this answer Creative Commons License