Calculate ph of solution labelled 2.6 M NaOH?

Question

4009 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-07T19:24:50

$color(blue)"pH = 14.415"$

Sodium hydroxide and Water is an exothermic reaction (heat generation):

$NaOH(s) + H_2O(l)$ $=>$ $Na^+$ + $OH^-$ + $H_2 O$ + HEAT

NaOH is a strong base and it is dissociate completely into Na+ and OH-.

DATA
[OH-] = 2.6 M
[H+] = Unknown

PURPOSE
Determine pOH
Calculate pH using equation: pH + pOH = 14

$pOH = -log [2.6]$
pOH = - 0.415

pH - 0.415 = 14

$color(blue)"pH = 14.415"$

A strong base has a high pH (>7).

NOTE:
pH is outside of the normal 1-14 range due to its concentration exceeds the maximum value of the previous pH-range of 1M.