How many g of sodium carbonate (molecular mass = 106) should be dissolved in 100 ml of water to make a 0.15 M solution?

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Answer 1 · 2018-04-08T23:29:06

1.59 g of $Na_2CO_3$

$Molarity$ = $"moles of solute"/"volume of solvent"$

PURPOSE
To use molarity concept (mol/L) to determine the mass of sodium carbonate.

$0.15 "mol"/L$ = $(Na_2CO_3)/"0.100 L"$

Solving,

$Na_2CO_3$ = 0.015 mol

Finally, converting moles to grams:

$("106 g"/cancel"mol")$ $0.015 cancel"mol"$ = 1.59 g of $Na_2CO_3$