Question

How do you simplify `\frac { 9^ { 4} p ^ { 5} q ^ { 8} } { 9^ { 2} p q ^ { 2} }`?

Answer 1

`81p^4q^6`

Explanation:

First, you have to know that when you multiply exponents with like bases you add the exponents and when you divide exponents with like bases you subtract the exponents.

In this case, we are dividing exponents with the same bases so we will subtract the exponents.

`9^4/9^2 ->4-2=2-> 9^2 = 81`

`p^5/p = p^5/p^1 ->5-1=4-> p^4`

`q^8/q^2->8-2=6-> q^6`

So we simplified it down to

`81p^4q^6`