Question

How do you simplify `2div sqrt2`?

Answer 1

`sqrt2`

Explanation:

`2-:sqrt2`
`rArr (sqrt2)^2 -: sqrt2`
`rArr (sqrt2)^2/sqrt2`
`rArr (sqrt2)^(2-1)`
Law of indices : `a^m/a^n =a^(m-n)`
`rArr sqrt2`

That's it,
Hope this helps :)