How do you multiply $7 (3 y - 4) + 2 (4 y + 3)$ $7(3y-4) + 2(4y+3)$ ?

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Answer 1 · 2018-04-09T14:12:19

$29 y - 22$ $29y-22$

= $7 (3 y - 4) + 2 (4 y + 3)$ $7(3y-4)+2(4y+3)$

= $21 y - 28 + 8 y + 6$ $21y-28+8y+6$

= $29 y - 22$ $29y-22$

Hope it helps!

How do you multiply 7(3y-4) + 2(4y+3)7(3y−4)+2(4y+3)7(3y-4) + 2(4y+3)?