What is the derivative of $f (x) = \frac{1}{{sin}^{2} x + {cos}^{2} x}$ $f(x)=1/(sin^2x+cos^2x)$ ?

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Answer 1 · 2018-04-09T15:10:08

$0$ $0$

$f (x) = \frac{1}{{sin}^{2} x + {cos}^{2} x} = \frac{1}{1} = 1$ $f(x) = 1/(sin^2x+cos^2x) = 1/1 = 1$ ,

so, $f'(x) = 0$ .

What is the derivative of f(x)=1/(sin^2x+cos^2x)f(x)=1sin2x+cos2xf(x)=1/(sin^2x+cos^2x)?