How can you differentiate y=IN(x^2+3)?

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Answer 1 · 2018-04-09T17:49:48

Look below

You have 2 functions, #ln(x) and x^2+3#

apply the chain rule, #u'(v)*v'#

#\frac{1}{x^2+3}*2x#

#\frac{2x}{x^2+3}#

Prove if its right?

Integrate!

#int \frac{2x}{x^2+3}dx#

use u-substitution

#u=x^2+3 -> dx = 1/(2x)du#

#int 1/u du = ln(u)#

#ln(x^2+3) +C#