What is the solution set of ${(h - 6)}^{2} = 400$ $(h-6)^2=400$ ?

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Answer 1 · 2018-04-10T01:44:22

26.

You are solving for h here, so you would first square root both sides of the equation to get

h-6=20.

Then you add 6 to both sides to get

h=26.

Answer 2 · 2018-04-10T01:54:01

The two solutions are $h = 26$ $h=26$ and $h = - 14$ $h=-14$ .

You can square root both sides to cancel the power:

${(h - 6)}^{2} = 400$ $(h-6)^2=400$

$\sqrt{{(h - 6)}^{2}} = \sqrt{400}$ $color(red)sqrt(color(black)((h-6)^2))=color(red)sqrtcolor(black)400$

$h - 6 = \sqrt{400}$ $h-6=color(red)sqrtcolor(black)400$

$h - 6 = \pm 20$ $h-6=+-20$

Solve each equation separately for two solutions:

$h - 6 = 20$ $h-6=20$

$h = 26$ $h=26$

And:

$h - 6 = - 20$ $h-6=-20$

$h = - 14$ $h=-14$

Those are the two solutions. Hope this helped!

What is the solution set of (h−6)2=400(h-6)^2=400?