Question

A cylinder of volume 1m3 is filled with 1kg of CO and 100g of H2O. What is the molar percentage of CO in the mixture in the cylinder?

Answer 1

87%

Explanation:

in 1 kg of CO you have `n= g/(MM)=(1000g)/(28g/(mol))=35,7 mol`
in 100 g of `H_2O` you have `n= g/(MM)=(100g)/(18g/(mol))=5,5 mol`
total mol = 35,7 + 5,5 = 41,2 mol
Molar percentage of CO =`(mol CO)/(mol_(t)) xx 100 =35.7/41.2=87%`