How many grams of sulfuric acid can be produced by 3 moles of SO3?

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How many grams of sulfuric acid can be produced by 3 moles of SO3?

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Answer 1 · 2018-04-10T21:53:42

294.27g

Explanation:

First, find the number of moles (or amount) of sulfuric acid (or $H_{2} S O_{4}$ $H_2SO_4$ ) that is produced

$S O_{3} + H_{2} O$ $SO_3+H_2O$ --> $H_{2} S O_{4}$ $H_2SO_4$

First, look at the stoichiometric coefficients (i.e. the big numbers in front of each substance. When there is no number written, that means the stoichiometric coefficient is 1).

$1 S O_{3} + 1 H_{2} O$ $1SO_3+1H_2O$ --> $1 H_{2} S O_{4}$ $1H_2SO_4$

What this is saying is that when 1 mole of $S O_{3}$ $SO_3$ reacts with 1 mole of $H_{2} O$ $H_2O$ , 1 mole of $H_{2} S O_{4}$ $H_2SO_4$ is produced.

So, when 3 moles of $S O_{3}$ $SO_3$ is used, 3 moles of $H_{2} S O_{4}$ $H_2SO_4$ is produced

To find the mass of $H_{2} S O_{4}$ $H_2SO_4$ produced, multiply the number of moles by the molar mass of $H_{2} S O_{4}$ $H_2SO_4$ .

Molar mass: $2 (1.01) + 32.07 + 4 (16.00) = 98.09$ $2(1.01)+32.07+4(16.00)=98.09$ $g m o l^{- 1}$ $gmol^-1$

3 x 98.09 = 294.27g

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How many grams of sulfuric acid can be produced by 3 moles of SO3?

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