2+log√1+x+3log√1-x=log √1-x^2. Solve for x?
1 Answer
Explanation:
I'm assuming you wish for us to solve
#2 + logsqrt(1 + x) + 3logsqrt(1 -x) = logsqrt(1 - x^2)#
We must apply the logarithm laws:
#2 + logsqrt(1 + x) + 3logsqrt(1 - x) = logsqrt((1 + x)(1 -x))#
#2 + 1/2log(1+ x) + 3/2log(1 -x) = 1/2log((1 + x)(1 -x))#
#2 + 1/2log(1+ x) + 3/2log(1- x) = 1/2log(1 + x) + 1/2log(1 -x)#
#log(1 - x) = -2#
#10^-2=1-x#
#x=1-10^-2#
#x = 1-1/100#
#x=99/100=0.99#
Hopefully this helps!
