How do you simplify $\frac{y^{2} + 9 y + 14}{y^{2} + 3 y + 2}$ $\frac { y ^ { 2} + 9y + 14} { y ^ { 2} + 3y + 2}$ ?

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Answer 1 · 2018-04-11T09:58:29

$\frac{y + 7}{y + 1}$ $(y+7)/(y+1)$

$\frac{y^{2} + 9 y + 14}{y^{2} + 3 y + 2}$ $(y^2+9y+14)/(y^2+3y+2)$

$= \frac{(y + 2) (y + 7)}{(y + 2) (y + 1)}$ $=((y+2)(y+7))/((y+2)(y+1))$ factorise trinomials

$= \frac{y + 7}{y + 1}$ $=(y+7)/(y+1)$ divide numerator and denominator by $y + 2$ $y+2$

Answer 2 · 2018-04-11T09:59:51

$\frac{x + 7}{x + 1}$ $(x+7)/(x+1)$

Factorise both the numerator and denominator

$\frac{(y + 7) (y + 2)}{(y + 2) (y + 1)}$ $((y+7)(y+2))/((y+2)(y+1))$

Cancel out the (x+2) on both the top and bottom

$\frac{y + 7}{y + 1}$ $(y+7)/(y+1)$

How do you simplify y2+9y+14y2+3y+2\frac { y ^ { 2} + 9y + 14} { y ^ { 2} + 3y + 2}?