Find |u| ? U=<2,-3>

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Answer 1 · 2018-04-11T12:23:40

$|\u|$ asks for the length of the vector.

In other words, you just need to use pythagoras theorem.

$|\u| = sqrt((2)^2+(-3)^2)$

$|\u| = sqrt(13)$

Answer 2 · 2018-04-11T12:56:46

$|u|=sqrt13$

$"given "ulu=< x,y>" then the magnitude is"$

$|ulu|=sqrt(x^2+y^2)$

$"here "x=2" and "y=-3$

$rArr|ulu|=sqrt(2^2+(-3)^2)=sqrt13$