A particle moves along the x axis. The velocity of the particle at t is 6t-t^2 . what is the distance travelled by the object between t=0 and t=3?
1 Answer
Apr 12, 2018
See the answer below...
Explanation:
- The velocity of the particle changes with the time as a relation
#color(red)(v=6t-t^2# - Then, the displacement of the particle is,
#(ds)/(dt)=6t-t^2#
#=>ds=(6t-t^2)dt#
#=>s=int_0^3ds=int_0^3(6t-t^2)dt=[3t^2-t^3/3]_0^3#
#=>s=3xx3^2-3^3/3=18# The displacement of the object is
#18"unit"# Hope it helps..
Thank you...
:-)
