What is the perimeter of a triangle with corners at (2,5), (9,2), and (3,8)?

1 Answer
Jarob R G.
Apr 12, 2018

√58+√72+√10

Explanation:

This requires you to apply the distance formula three times. Recall that the distance between two points (x1,y1) and (x2,y2) is D=√(x2−x1)2+(y2−y1)2.

The distance between (2,5) and (9,2) is D1=√(9−2)2+(2−5)2=√49+9=√58.

The distance between (9,2) and (3,8) is D2=√(3−9)2+(8−2)2=√36+36=√72.

The distance between (3,8) and (2,5) is D3=√(2−3)2+(5−8)2=√1+9=√10.

The perimeter is thus P=D1+D2+D3=√58+√72+√10.

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