How do you solve $\frac{8}{7} - \frac{13}{14} = \frac{1}{x}$ $\frac { 8} { 7} - \frac { 13} { 14} = \frac { 1} { x }$ ?

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How do you solve $\frac{8}{7} - \frac{13}{14} = \frac{1}{x}$ $\frac { 8} { 7} - \frac { 13} { 14} = \frac { 1} { x }$ ?

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Answer 1 · 2018-04-13T12:00:13

$\frac{8}{7} - \frac{13}{14} = \frac{1}{x}$ ${ 8}/ { 7} - \frac { 13} { 14} = \frac { 1} { x }$
$x = \frac{14}{3}$ $x=14/3$

Explanation:

$\frac{8}{7} - \frac{13}{14} = \frac{1}{x}$ $\frac { 8} { 7} - \frac { 13} { 14} = \frac { 1} { x }$
$\frac{2 \cdot 8 - 13}{14} = \frac{1}{x}$ $(2*8-13)/14=1/x$
$\frac{16 - 13}{14} = \frac{1}{x}$ $(16-13)/14=1/x$
$\frac{3}{14} = \frac{1}{x}$ $3/14=1/x$
$\frac{14}{3} = \frac{x}{1}$ $14/3=x/1$
$x = \frac{14}{3}$ $x=14/3$

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How do you solve $\frac{8}{7} - \frac{13}{14} = \frac{1}{x}$ $\frac { 8} { 7} - \frac { 13} { 14} = \frac { 1} { x }$ ?

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Explanation:

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How do you solve $\frac{8}{7} - \frac{13}{14} = \frac{1}{x}$ $\frac { 8} { 7} - \frac { 13} { 14} = \frac { 1} { x }$ ?