If #h(x) = -x^2 - 3x#, how do you solve h(-4)?
2 Answers
Apr 14, 2018
h(-4) = -4
Explanation:
Since x is given (x = -4). Then, all you need to do is log in -4 for each value of x
h(-4) =
h(-4) = -(16) + 12 = -4
Apr 14, 2018