How do you evaluate $3 m - n (m^{2} - 4)$ $3m-n(m^2-4)$ if $m = 2$ $m=2$ and $n = 5$ $n=5$ ?

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How do you evaluate $3 m - n (m^{2} - 4)$ $3m-n(m^2-4)$ if $m = 2$ $m=2$ and $n = 5$ $n=5$ ?

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Answer 1 · 2018-04-14T09:33:47

$3 m - n (m^{2} - 4) = 6$ $3m-n(m^2-4)=6$
$m = 2$ $m=2$
$n = 5$ $n=5$

Explanation:

Put the given numbers in the expression:
$3 \cdot 2 - 5 \cdot (2^{2} - 4) =$ $3*2-5*(2^2-4)=$
$= 6 - 5 \cdot (4 - 4) =$ $=6-5*(4-4)=$
$= 6 - 5 \cdot 0 =$ $=6-5*0=$ 6

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How do you evaluate $3 m - n (m^{2} - 4)$ $3m-n(m^2-4)$ if $m = 2$ $m=2$ and $n = 5$ $n=5$ ?

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How do you evaluate $3 m - n (m^{2} - 4)$ $3m-n(m^2-4)$ if $m = 2$ $m=2$ and $n = 5$ $n=5$ ?