How do you solve $3 (\frac{5}{6} - 2 k) + \frac{5}{2} (3 k - 2) = 8$ $3( \frac { 5} { 6} - 2k ) + \frac { 5} { 2} ( 3k - 2) = 8$ ?

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Answer 1 · 2018-04-15T18:00:33

$k = 7$ $k=7$

$3 (\frac{5}{6} - 2 k) + \frac{5}{2} (3 k - 2) = 8$ $3(5/6-2k)+5/2(3k-2)=8$

$\frac{15}{6} - 6 k + \frac{15}{2} \cdot k - \frac{10}{2} = 8$ $15/6-6k+15/2*k-10/2=8$

$\frac{15}{6} - 6 k + \frac{15}{2} \cdot k - 5 = 8$ $15/6-6k+15/2*k-5=8$ multiply both sides by $6$ $6$

$6 \cdot \frac{15}{6} - 6 \cdot 6 k + 6 \cdot \frac{15}{2} \cdot k - 6 \cdot 5 = 6 \cdot 8$ $6*15/6-6*6k+6*15/2*k-6*5=6*8$

$cancelcolor(red)6*15/cancelcolor(red)6-6*6k+color(green)3cancelcolor(red)6*15/cancelcolor(red)2*k-6*5=6*8$

$15-36k+45k-30=48$

$-36k+45k=48+30-15$

$9k=63$ divide both sides by $9$

$(9k)/9=63/9$

$(color(red)cancel9k)/color(red)9=7$

$k=7$

How do you solve 3( \frac { 5} { 6} - 2k ) + \frac { 5} { 2} ( 3k - 2) = 83(56−2k)+52(3k−2)=83( \frac { 5} { 6} - 2k ) + \frac { 5} { 2} ( 3k - 2) = 8?