How do you solve $8 (x - 2) = x + 19$ $8(x-2) = x + 19$ ?

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Answer 1 · 2018-04-15T18:30:11

$x = 5$ $x=5$

We can start by distributing the $8$ $8$ to both terms in the parenthesis on the left hand side. Doing this, we get:

$8 x - 16 = x + 19$ $8x-16=x+19$

Our next step would be to add $16$ $16$ to both sides to get:

$8 x = x + 35$ $8x=x+35$

Next, we can subtract $x$ $x$ from both sides to get:

$7 x = 35$ $7x=35$

Our last step would be to divide both sides by $7$ $7$ to get:

$x = 5$ $x=5$

Hope this helps!

Answer 2 · 2018-04-15T18:31:08

$x = 5$ $x=5$

First expand brackets

$8 x - 16 = x + 19$ $8x-16=x+19$

Next add 16 to both sides

$8 x = x + 35$ $8x=x+35$

Then take x from both sides

$7 x = 35$ $7x=35$

Finally, divide both sides by 7

$x = 5$ $x=5$

How do you solve 8(x-2) = x + 198(x−2)=x+198(x-2) = x + 19?