How do you find the additive and multiplicative inverse of -8/3?

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How do you find the additive and multiplicative inverse of -8/3?

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Answer 1 · 2018-04-15T23:22:20

The additive inverse is $\frac{8}{3}$ $8/3$ .
The multiplicative inverse is $- \frac{3}{8}$ $-3/8$ .

Explanation:

When a number is added to its additive inverse, the result zero. When a number is multiplied to its multiplicative inverse, the result is 1.

Solving for the additive inverse:
$- \frac{8}{3} + x = 0$ $-8/3+x=0$
(add $\frac{8}{3}$ $8/3$ to both sides):
$x = \frac{8}{3}$ $x=8/3$

Solving for the multiplicative inverse:
$- \frac{8}{3} \cdot x = 1$ $-8/3*x=1$
(divide both sides by $- \frac{8}{3}$ $-8/3$ ):
$x = - \frac{3}{8}$ $x=-3/8$

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How do you find the additive and multiplicative inverse of -8/3?

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