How do you solve $3(x-1)-4(x-3)=0$ ?

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Answer 1 · 2018-04-16T01:52:09

$x=9$

$3(x-1)-4(x-3)=0$

Start with the distributive property

$(3)(x)+(3)(-1)+(-4)(x)+(-4)(-3)=0$

$3x - 3 - 4x + 12 =0$

$-x + 9 = 0$

Subtract $9$ on both sides

$-x + 9 - 9 = 0 - 9$

$-x = -9$

Multiply both sides by $-1$

$-x xx-1 = -9 xx -1$

$x = 9$

How do you solve 3(x-1)-4(x-3)=03(x-1)-4(x-3)=0?