How do you find the indefinite integral of ∫ x^2 - 2 dx / x^3 - 4x ?
2 Answers
Apr 15, 2018
Explanation:
We want to solve
#I=int(x^2-2)/(x^3-4x)dx#
Multiply the DEN and NUM by
#I=int(x^3-2x)/(x^4-4x^2)dx#
Now we can make i nice substitution
#I=1/4int1/udu#
#color(white)(I)=1/4ln(u)+C#
#color(white)(I)=1/4ln(x^4-4x^2)+C#
Apr 16, 2018
I have solved this way, applying partial fractions decomposition: