How do you solve the equations $8x + 3y = 16$ and $2x + y = 4$ ?

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Answer 1 · 2018-04-16T18:44:03

$x=2$ , $y=0$

There are different methods to solve these equations.

Solving using the Elimination method

Consider the given equations:

$8x+3y=16$ . . . . . (1)
$2x+y=4$ . . . . . (2)

In order to make the coefficients of the variable 'y' the same, multiply equation (2) with 3.

Then,
$6x+3y=12$ . . . . . (3)

Now, in order to eliminate the variable 'y', subtract (3) from (1).

Then we get,
$2x+0y=4$

That is,
$2x=4$
$x=4/2$
$x=2$

Now, substitute this value in (2).

Then,
$2(2)+y=4$
$4+y=4$
$y=4-4$
$y=0$

How do you solve the equations 8x + 3y = 168x + 3y = 16 and 2x + y = 42x + y = 4?